Question Number 68629 by TawaTawa last updated on 14/Sep/19
![](https://www.tinkutara.com/question/9281.png)
Answered by $@ty@m123 last updated on 14/Sep/19
![∠XYT=∠XTP ⇒∠XYT=50^o Let ∠YXT=∠XTY=x ⇒x+x+50^o =180^o ⇒x=((130)/2) ⇒∠YXT=50^o ⇒∠TZY=50^o](https://www.tinkutara.com/question/Q68647.png)
$$\angle{XYT}=\angle{XTP} \\ $$$$\Rightarrow\angle{XYT}=\mathrm{50}^{\mathrm{o}} \\ $$$$\mathrm{L}{et}\:\angle{YXT}=\angle{XTY}={x} \\ $$$$\Rightarrow{x}+{x}+\mathrm{50}^{\mathrm{o}} =\mathrm{180}^{\mathrm{o}} \\ $$$$\Rightarrow{x}=\frac{\mathrm{130}}{\mathrm{2}} \\ $$$$\Rightarrow\angle{YXT}=\mathrm{50}^{\mathrm{o}} \\ $$$$\Rightarrow\angle{TZY}=\mathrm{50}^{\mathrm{o}} \: \\ $$
Commented by TawaTawa last updated on 17/Sep/19
![God bless you sir](https://www.tinkutara.com/question/Q68999.png)
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$