Question Number 68808 by aseer imad last updated on 15/Sep/19
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Answered by JDamian last updated on 15/Sep/19
![I=(V/R)=((10)/(1+3+6))=1 A E_c =(1/2)CV^2 E=(1/2)(10×10^(−6) × 3^2 + 20×10^(−6) ×9^2 )= = 855×10^(−6) J](https://www.tinkutara.com/question/Q68811.png)
$${I}=\frac{{V}}{{R}}=\frac{\mathrm{10}}{\mathrm{1}+\mathrm{3}+\mathrm{6}}=\mathrm{1}\:{A} \\ $$$$ \\ $$$${E}_{{c}} =\frac{\mathrm{1}}{\mathrm{2}}{CV}^{\mathrm{2}} \\ $$$$ \\ $$$${E}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{10}×\mathrm{10}^{−\mathrm{6}} \:×\:\mathrm{3}^{\mathrm{2}} \:+\:\mathrm{20}×\mathrm{10}^{−\mathrm{6}} ×\mathrm{9}^{\mathrm{2}} \right)= \\ $$$$\:\:\:\:=\:\mathrm{855}×\mathrm{10}^{−\mathrm{6}} \:{J} \\ $$