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sin-t-i-di-dt-i-0-0-i-t-




Question Number 730 by 123456 last updated on 04/Mar/15
sin t=i(di/dt)  i(0)=0  i(t)=?
$$\mathrm{sin}\:{t}={i}\frac{{di}}{{dt}} \\ $$$${i}\left(\mathrm{0}\right)=\mathrm{0} \\ $$$${i}\left({t}\right)=? \\ $$
Commented by malwaan last updated on 05/Mar/15
−cos t=(i^2 /2)+C   i(t)=(√(C−2cos t))  i(0)=(√(C−2))=0   C=2  i(t)=(√(2−2cos t))    Am I right ???
$$−{cos}\:{t}=\frac{{i}^{\mathrm{2}} }{\mathrm{2}}+{C}\: \\ $$$${i}\left({t}\right)=\sqrt{{C}−\mathrm{2}{cos}\:{t}} \\ $$$${i}\left(\mathrm{0}\right)=\sqrt{{C}−\mathrm{2}}=\mathrm{0}\:\:\:{C}=\mathrm{2} \\ $$$${i}\left({t}\right)=\sqrt{\mathrm{2}−\mathrm{2}{cos}\:{t}} \\ $$$$ \\ $$$${Am}\:{I}\:{right}\:??? \\ $$
Commented by prakash jain last updated on 05/Mar/15
Solution is correct. What about −(√(2−2cos t))?
$$\mathrm{Solution}\:\mathrm{is}\:\mathrm{correct}.\:\mathrm{What}\:\mathrm{about}\:−\sqrt{\mathrm{2}−\mathrm{2cos}\:{t}}? \\ $$
Commented by malwaan last updated on 05/Mar/15
It is  also solution
$${It}\:{is}\:\:{also}\:{solution} \\ $$$$ \\ $$

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