Question Number 134 by novrya last updated on 25/Jan/15
![Solve for 3x≡4 (mod 5)](https://www.tinkutara.com/question/Q134.png)
$${Solve}\:{for}\:\mathrm{3}{x}\equiv\mathrm{4}\:\left({mod}\:\mathrm{5}\right) \\ $$
Answered by rajabhay last updated on 09/Dec/14
![gcd(3,5)=1 and 1 divides 4 There is only solution x=3 (mod 5)](https://www.tinkutara.com/question/Q135.png)
$$\mathrm{gcd}\left(\mathrm{3},\mathrm{5}\right)=\mathrm{1}\:\mathrm{and}\:\mathrm{1}\:\mathrm{divides}\:\mathrm{4}\: \\ $$$$\mathrm{There}\:\mathrm{is}\:\mathrm{only}\:\mathrm{solution}\: \\ $$$${x}=\mathrm{3}\:\left({mod}\:\mathrm{5}\right) \\ $$