Question Number 66173 by Tony Lin last updated on 10/Aug/19
![x^x^(x∙^.^(.x) ) =2 x=?](https://www.tinkutara.com/question/Q66173.png)
$${x}^{{x}^{{x}\centerdot^{.^{.{x}} } } } =\mathrm{2} \\ $$$${x}=? \\ $$
Answered by mr W last updated on 10/Aug/19
![x>0 x^2 =2 x=(√2)](https://www.tinkutara.com/question/Q66177.png)
$${x}>\mathrm{0} \\ $$$${x}^{\mathrm{2}} =\mathrm{2} \\ $$$${x}=\sqrt{\mathrm{2}} \\ $$