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Question-30106




Question Number 30106 by naka3546 last updated on 16/Feb/18
Answered by mrW2 last updated on 16/Feb/18
Commented by mrW2 last updated on 16/Feb/18
((DG)/(AD))=((EF)/(AF))  ⇒((DG)/8)=(6/(AF))  ⇒AF×DG=6×8=48  [ABF]=[AFD]=(1/2)AF×DG=((48)/2)=24
$$\frac{{DG}}{{AD}}=\frac{{EF}}{{AF}} \\ $$$$\Rightarrow\frac{{DG}}{\mathrm{8}}=\frac{\mathrm{6}}{{AF}} \\ $$$$\Rightarrow{AF}×{DG}=\mathrm{6}×\mathrm{8}=\mathrm{48} \\ $$$$\left[{ABF}\right]=\left[{AFD}\right]=\frac{\mathrm{1}}{\mathrm{2}}{AF}×{DG}=\frac{\mathrm{48}}{\mathrm{2}}=\mathrm{24} \\ $$
Commented by ajfour last updated on 16/Feb/18
Great question, awesome solution, Sir !
$${Great}\:{question},\:{awesome}\:{solution},\:{Sir}\:! \\ $$

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