Question-207712

Question Number 207712 by efronzo1 last updated on 24/May/24

Answered by Frix last updated on 24/May/24

For x = q and A = (\begin{matrix} p \\ 0 \end{matrix}) the area is (q - p) \sqrt{p}

\frac{d [(q - p) \sqrt{p}]}{d p} = 0

\frac{q - 3 p}{2 \sqrt{p}} = 0 \Rightarrow p = \frac{q}{3}

Max area = \frac{2 \sqrt{3} q^{\frac{3}{2}}}{9}

q = 4 \Rightarrow answer is \frac{16 \sqrt{3}}{9}

Facebook Tweet Pin