Question Number 218658 by Nicholas666 last updated on 14/Apr/25 Answered by Nicholas666 last updated on 14/Apr/25 Commented by A5T last updated on 14/Apr/25 $$\mathrm{x}\leqslant\mathrm{3}\:\mathrm{and}\:\mathrm{y}\geqslant\mathrm{1}\:\mathrm{does}\:\mathrm{not}\:\mathrm{imply}\:\mathrm{xy}\leqslant\mathrm{3} \\…
Question Number 218652 by Tawa11 last updated on 14/Apr/25 Angle of incidence is 40° if the direction of the incidence ray is constant and the…
Question Number 218719 by sadeq last updated on 14/Apr/25 Commented by Nicholas666 last updated on 14/Apr/25 $$\:\:\: \\ $$$$\:\:\:{what}\:{is}\:??? \\ $$$$ \\ $$ Terms of…
Question Number 218713 by Nicholas666 last updated on 14/Apr/25 Commented by Nicholas666 last updated on 14/Apr/25 $$\:\:\:{Hello}\:{friends},\: \\ $$$$\:{let}'{s}\:{solve}\:{the}\:{integral}\:{problem} \\ $$ Commented by Nicholas666 last…
Question Number 218709 by Nicholas666 last updated on 14/Apr/25 $$ \\ $$$$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \:\frac{{d}\theta}{\:\sqrt{{sin}\theta\:+{cos}\theta}} \\ $$$$ \\ $$ Answered by Nicholas666 last updated on 14/Apr/25…
Question Number 218703 by Nicholas666 last updated on 14/Apr/25 $$ \\ $$$$\:\:\:\:{Prove};\:{lim}_{{x}\rightarrow\mathrm{0}} \:\frac{{x}\:−\:{sin}\:{x}}{{x}^{\mathrm{3}} }\:=\:\frac{\mathrm{1}}{\mathrm{6}}\:\: \\ $$$$ \\ $$ Answered by SdC355 last updated on 14/Apr/25…
Question Number 218648 by Spillover last updated on 13/Apr/25 Answered by Spillover last updated on 14/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218649 by Spillover last updated on 13/Apr/25 Answered by Spillover last updated on 14/Apr/25 Answered by Spillover last updated on 14/Apr/25 Terms of…
Question Number 218650 by Spillover last updated on 13/Apr/25 Answered by Spillover last updated on 14/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218651 by hardmath last updated on 13/Apr/25 Answered by vnm last updated on 14/Apr/25 $$=\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}−\mathrm{4}\centerdot\frac{\mathrm{1}}{\mathrm{4}}\right)+ \\ $$$$\left(\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{6}}+\frac{\mathrm{1}}{\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{8}}−\mathrm{4}\centerdot\frac{\mathrm{1}}{\mathrm{8}}\right)+ \\ $$$$…+ \\ $$$$\left(\frac{\mathrm{1}}{\mathrm{4}{n}−\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}{n}−\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{4}{n}−\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{4}{n}}−\mathrm{4}\centerdot\frac{\mathrm{1}}{\mathrm{4}{n}}\right)= \\ $$$$\underset{{k}=\mathrm{1}}…