Question Number 10620 by Saham last updated on 20/Feb/17 Commented by mrW1 last updated on 20/Feb/17 $${please}\:{check}: \\ $$$${after}\:{collision}\:\overset{\rightarrow} {{V}}_{{A}} =−\mathrm{5}.\mathrm{0}{i}+\mathrm{20}{j}\:\:\:\left({not}\:−\mathrm{5}.\mathrm{0}{j}+\mathrm{20}{j}\right) \\ $$$${answer}\:\left({b}\right)\:\mathrm{500}\:{J}\:\:\:\left({not}\:\mathrm{525}\:{J}\right) \\ $$…
Question Number 141608 by cherokeesay last updated on 21/May/21 Commented by cherokeesay last updated on 21/May/21 $${the}\:{area}\:{hatched}\:? \\ $$ Answered by MJS_new last updated on…
Question Number 10513 by ssparasmani@gmail.com last updated on 15/Feb/17 $${e}^{\left(−\mathrm{2}×\mathrm{10}^{−\mathrm{2}} /\mathrm{2}\right)} \\ $$ Commented by robocop last updated on 16/Feb/17 $${verifica}\:{los}\:{signos}\:{de}\:{agrupacion}\:{y}\:{te}\:{ayudo}.\:{Salu}\mathrm{2}. \\ $$ Terms of…
Question Number 10480 by ssparasmani@gmail.com last updated on 13/Feb/17 $${d}/{dx}\left(\mathrm{cos}\:^{\mathrm{2}} {xdy}/{dx}\right)=\mathrm{0} \\ $$$$ \\ $$ Answered by mrW1 last updated on 13/Feb/17 $${d}/{dx}\left(\mathrm{cos}\:^{\mathrm{2}} {xdy}/{dx}\right)=\mathrm{0} \\…
Question Number 10477 by ABCDEFGH last updated on 14/Feb/17 $${maximum}\:{and}\:{minimum}\:{value}\:{of}\: \\ $$$$\mathrm{12}{x}^{\mathrm{5}−\mathrm{5}{x}^{\mathrm{4}_{+\mathrm{40}{x}^{\mathrm{3}_{+\mathrm{6}} } } } } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10435 by Joel575 last updated on 09/Feb/17 Commented by Joel575 last updated on 09/Feb/17 $$\mathrm{The}\:\mathrm{side}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\mathrm{1}\:\mathrm{cm}. \\ $$$$\mathrm{5}\:\mathrm{circles}\:\mathrm{have}\:\mathrm{same}\:\mathrm{radius}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}'\mathrm{s}\:\mathrm{radius}? \\ $$ Answered by…
Question Number 10426 by JAZAR last updated on 10/Feb/17 $${good}\:{morning}!!!! \\ $$$${we}\:{have}\:\:{f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{2}{x}\:\:\:{g}\left({x}\right)=−\mathrm{2}{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2} \\ $$$${and}\:{d}\left({m}\right)={mx}+\mathrm{2}{m} \\ $$$$\left.\mathrm{1}\right){determine}\:{the}\:{coordonate}\:{of}\:{M}_{\mathrm{1}} \:{and}\:{M}_{\mathrm{2}} \: \\ $$$${intersection}\:{points}\:{respectively}\:{of}\:\left({Cf}\right)\:{and}\:{d}\left({m}\right) \\ $$$${or}\left({Cg}\right)\:{and}\:{d}\left({m}\right) \\…
Question Number 10415 by okhema francis last updated on 08/Feb/17 $${find}\:{all}\:{the}\:{possible}\:{values}\:{of}\:\mathrm{cos}\:\theta\:{such}\:{that}\:\mathrm{2cot}\:^{\mathrm{2}} \theta\:+\:\mathrm{cos}\:\theta=\mathrm{0} \\ $$$$ \\ $$ Answered by bansal22luvi@gmail.com last updated on 08/Feb/17 $$\mathrm{2}\left(\frac{\mathrm{cos}^{\mathrm{2}} \theta}{\mathrm{sin}^{\mathrm{2}}…
Question Number 75849 by behi83417@gmail.com last updated on 18/Dec/19 $$\boldsymbol{\mathrm{In}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{A}}\overset{\bigtriangleup} {\boldsymbol{\mathrm{B}C}}: \\ $$$$\begin{cases}{\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}+\boldsymbol{\mathrm{c}}=\mathrm{2}\left(\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} \right)}\\{\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{b}}^{\mathrm{2}} +\boldsymbol{\mathrm{c}}^{\mathrm{2}} =\mathrm{6}\boldsymbol{\mathrm{abc}}}\\{\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{2}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} ^{\mathrm{2}} +\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} ^{\mathrm{2}} =\mathrm{6}\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}}…
Question Number 10303 by amir last updated on 02/Feb/17 Commented by amir last updated on 02/Feb/17 $${triangle}\:{ABC}\:\:{is}\:{isoscale}.{BA}={BC} \\ $$$${find}\:\:\:\:\boldsymbol{{x}}. \\ $$ Terms of Service Privacy…