Question Number 47235 by Rio Michael last updated on 06/Nov/18 $${the}\:{force}\:{acting}\:{on}\:{a}\:{particle}\:{P}\:{of}\:{mass}\:\:\mathrm{2}{kg}\:{is}\:\left(\mathrm{2}{ti}\:+\mathrm{4}{j}\right){N}. \\ $$$${P}\:{is}\:{initially}\:{at}\:{rest}\:{at}\:{point}\:{with}\:{position}\:{vector}\:\left({i}+\mathrm{2}{j}\right). \\ $$$${Find}\:{the}\:{velocity}\:{of}\:{P}\:{when}\:{t}=\mathrm{2}\:{and}\:{the}\:{position}\:{vector}\: \\ $$$${when}\:{t}=\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 47234 by Rio Michael last updated on 06/Nov/18 $${the}\:{force}\:{acting}\:{on}\:{a}\:{particle}\:{P}\:{of}\:{mass}\:\:\mathrm{2}{kg}\:{is}\:\left(\mathrm{2}{ti}\:+\mathrm{4}{j}\right){N}. \\ $$$${P}\:{is}\:{initially}\:{at}\:{rest}\:{at}\:{point}\:{with}\:{position}\:{vector}\:\left({i}+\mathrm{2}{j}\right). \\ $$$${Find}\:{the}\:{velocity}\:{of}\:{P}\:{when}\:{t}=\mathrm{2}\:{and}\:{the}\:{position}\:{vector}\: \\ $$$${when}\:{t}=\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 47233 by Rio Michael last updated on 06/Nov/18 $${the}\:{force}\:{acting}\:{on}\:{a}\:{particle}\:{P}\:{of}\:{mass}\:\:\mathrm{2}{kg}\:{is}\:\left(\mathrm{2}{ti}\:+\mathrm{4}{j}\right){N}. \\ $$$${P}\:{is}\:{initially}\:{at}\:{rest}\:{at}\:{point}\:{with}\:{position}\:{vector}\:\left({i}+\mathrm{2}{j}\right). \\ $$$${Find}\:{the}\:{velocity}\:{of}\:{P}\:{when}\:{t}=\mathrm{2}\:{and}\:{the}\:{position}\:{vector}\: \\ $$$${when}\:{t}=\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 47138 by Tawa1 last updated on 05/Nov/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 176723 by doline last updated on 25/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\left({i}−\mathrm{1}\right)^{\mathrm{5}} /\left({i}−\mathrm{4}\right)^{\mathrm{4}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 176719 by doline last updated on 25/Sep/22 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 111105 by bobhans last updated on 02/Sep/20 $$\mathrm{y}''+\mathrm{2y}'+\mathrm{y}=\mathrm{e}^{−\mathrm{2x}} +\mathrm{2x}+\mathrm{3} \\ $$ Commented by mohammad17 last updated on 02/Sep/20 $${r}^{\mathrm{2}} +\mathrm{2}{r}+\mathrm{1}=\mathrm{0}\Rightarrow\left({r}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{0}\Rightarrow{r}_{\mathrm{1}} ={r}_{\mathrm{2}} =−\mathrm{1}…
Question Number 176549 by doline last updated on 21/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\:{de}\:\mathrm{1}/\mathrm{4}\left({cos}\Pi/\mathrm{9}+{isin}\Pi/\mathrm{9}\right) \\ $$ Answered by Ar Brandon last updated on 21/Sep/22 $$\frac{\mathrm{1}}{\mathrm{4}\left(\mathrm{cos}\frac{\pi}{\mathrm{9}}+{i}\mathrm{sin}\frac{\pi}{\mathrm{9}}\right)}=\frac{\mathrm{1}}{\mathrm{4}{e}^{\frac{\pi}{\mathrm{9}}{i}} }=\frac{\mathrm{1}}{\mathrm{4}}{e}^{−\frac{\pi}{\mathrm{9}}{i}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{cos}\frac{\pi}{\mathrm{9}}−{i}\mathrm{sin}\frac{\pi}{\mathrm{9}}\right) \\…
Question Number 176379 by doline last updated on 17/Sep/22 $${lineariser}\:{sin}^{\mathrm{5}} \left({x}\right) \\ $$ Answered by a.lgnaoui last updated on 17/Sep/22 $$\mathrm{sin}\:^{\mathrm{5}} \left({x}\right)=\left(\frac{{e}^{{ix}} −{e}^{−{ix}} }{\mathrm{2}}\right)^{\mathrm{5}} \\…
Question Number 176366 by doline last updated on 17/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\:{de}\left(\mathrm{1}−{i}\sqrt{}\mathrm{3}\right)\left(\mathrm{1}+{i}\right)\left({cos}\theta−{isin}\theta\right) \\ $$ Answered by Ar Brandon last updated on 17/Sep/22 $$\left(\mathrm{2}{e}^{−\frac{\pi}{\mathrm{3}}{i}} \right)\left(\sqrt{\mathrm{2}}{e}^{\frac{\pi}{\mathrm{4}}{i}} \right)\left({e}^{−{i}\theta} \right)=\mathrm{2}\sqrt{\mathrm{2}}{e}^{\left(−\frac{\pi}{\mathrm{3}}+\frac{\pi}{\mathrm{4}}−\theta\right){i}} \\…