Question Number 215255 by Rasheed.Sindhi last updated on 01/Jan/25 $${a},{b},{c}\:{are}\:{pythagorean}\:{triples} \\ $$$${For}\:{the}\:{following}\:{values}: \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{5}}&\hline{\mathrm{12}}&\hline{\mathrm{13}}\\\hline\end{array}\:\:\underset{\Rightarrow\mathrm{5}^{\mathrm{2}} =\mathrm{12}+\mathrm{13}=\mathrm{25}} {{a}^{\mathrm{2}} ={b}+{c}\:\:} \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{45}}&\hline{\mathrm{1012}}&\hline{\mathrm{1013}}\\\hline\end{array}\underset{\:\:\:\:\:\:\:\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025}} {{a}^{\mathrm{2}} ={b}+{c}} \\ $$$$\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025}…
Question Number 215224 by ppch145 last updated on 31/Dec/24 $$\mathrm{I}\:\mathrm{have}\:\mathrm{just}\:\mathrm{discovered}\:\mathrm{that}\:\mathrm{it}\: \\ $$$$\mathrm{is}\:\mathrm{only}\:\mathrm{alphabetic}\:\mathrm{letters}\:\mathrm{that} \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{made}\:\mathrm{bold}\:\mathrm{while}\: \\ $$$$\mathrm{typing}\:\mathrm{with}\:\mathrm{the}\:\mathrm{keyboard}\:\mathrm{of}\: \\ $$$$\mathrm{this}\:\mathrm{app}.\:\mathrm{Numbers}\:\mathrm{0}\:-\:\mathrm{9}\:\mathrm{can}'\mathrm{t} \\ $$$$\mathrm{be}\:\mathrm{made}\:\mathrm{bold},\:\mathrm{after}\:\mathrm{being}\: \\ $$$$\mathrm{selected}.\: \\ $$$$ \\…
Question Number 215067 by Tawa11 last updated on 27/Dec/24 Commented by ajfour last updated on 27/Dec/24 https://youtu.be/X7ruXB1nU18?si=Qa91ch5ybcVcATkh Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 215032 by Tawa11 last updated on 26/Dec/24 Commented by Tawa11 last updated on 26/Dec/24 $$\mathrm{I}\:\mathrm{got}\:\:\mathrm{10}.\mathrm{3}\:\mathrm{m}/\mathrm{s} \\ $$ Answered by mr W last updated…
Question Number 214898 by ChantalYah last updated on 22/Dec/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 214781 by ppch145 last updated on 19/Dec/24 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{usefulness}\:\mathrm{of}\:“\mathrm{Get}\:\mathrm{Latex}''\mathrm{in}\:\mathrm{this}\: \\ $$$$\mathrm{application}? \\ $$ Commented by Tinku Tara last updated on 19/Dec/24 $$\mathrm{If}\:\mathrm{you}\:\mathrm{are}\:\mathrm{using}\:\mathrm{mobile}\:\mathrm{version}\:\mathrm{of} \\ $$$$\mathrm{word}\:\mathrm{then}\:\mathrm{using}\:\mathrm{image}\:\mathrm{will}\:\mathrm{be}…
Question Number 214757 by Tawa11 last updated on 19/Dec/24 Commented by ajfour last updated on 23/Dec/24 Hi, can you follow this question I have discussed. Really nice question, i created. https://youtu.be/PzKYmi7qrvk?si=TkeicIBzJ2aCaNZr Commented by Tawa11 last updated on 23/Dec/24 $$\mathrm{Followed}\:\mathrm{sir}…
Question Number 214569 by Atomic_30 last updated on 12/Dec/24 Answered by TonyCWX08 last updated on 12/Dec/24 $${What}\:{do}\:{you}\:{want}? \\ $$ Answered by MathematicalUser2357 last updated on…
Question Number 214448 by jahar last updated on 08/Dec/24 $$ \\ $$$$\overset{−} {{x}}\:=\:\frac{\Sigma{f}_{{i}} {x}_{{i}} }{\Sigma{f}_{{i}} \:}\:,\:\:\:\overset{−} {{u}}\:=\:\frac{\Sigma{f}_{{i}} {u}_{{i}} }{\Sigma{f}_{{i}} }\:,\:{u}\:=\:\frac{{x}−{a}}{{h}}\:, \\ $$$${proved}\:{that}\:\overset{−} {{x}}\:=\:{a}\:+\:{h}\overset{−} {{u}} \\…
Question Number 214264 by zhou0429 last updated on 03/Dec/24 Commented by Ghisom last updated on 05/Dec/24 $$\mathrm{it}\:\mathrm{makes}\:\mathrm{no}\:\mathrm{sense}\:\mathrm{trying}\:\mathrm{to}\:\mathrm{find}\:\mathrm{an}\:\mathrm{exact} \\ $$$$\mathrm{solution}\:\mathrm{since}\:\left(\mathrm{1}\right)\:\sqrt{\mathrm{39}}\:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\mathrm{zero}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{polynomial}\:\mathrm{and}\:\left(\mathrm{2}\right)\:\mathrm{the}\:\mathrm{real}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{polynomial}\:\mathrm{is}\:\mathrm{no}\:\mathrm{usable}\:\mathrm{expression} \\ $$$$\mathrm{just}\:\mathrm{use}\:\mathrm{a}\:\mathrm{good}\:\mathrm{calculator}…