Question Number 223591 by Tawa11 last updated on 31/Jul/25 Commented by ajfour last updated on 31/Jul/25 $${Very}\:{nice}\:{Question}! \\ $$ Commented by Tawa11 last updated on…
Question Number 223255 by profrey last updated on 19/Jul/25 $${Which}\:{of}\:{the}\:{following}\:{complex} \\ $$$${numbers}\:{is}\:{equivalent}\:{to}\:\frac{\mathrm{3}−\mathrm{5}{i}}{\mathrm{8}+\mathrm{2}{i}}?\left({Note}:\:{i}=\sqrt{\left.−\mathrm{1}\right)}\right. \\ $$$$\left.{A}\right)\frac{\mathrm{3}}{\mathrm{8}}−\frac{\mathrm{5}{i}}{\mathrm{2}} \\ $$$$ \\ $$$$\left.{B}\right)\frac{\mathrm{3}}{\mathrm{8}}+\frac{\mathrm{5}{i}}{\mathrm{2}} \\ $$$$\: \\ $$$$\left.{C}\right)\frac{\mathrm{7}}{\mathrm{34}}−\frac{\mathrm{23}{i}}{\mathrm{34}} \\ $$$$ \\…
Question Number 223101 by Jubr last updated on 14/Jul/25 Commented by Tawa11 last updated on 15/Jul/25 $$?\:\:=\:\:\frac{\mathrm{16}}{\mathrm{25}}\left(?\:\:+\:\:\mathrm{76}.\mathrm{5}\right) \\ $$$$\therefore\:\:\:\:?\:\:\:=\:\:\:\mathrm{136}\:\mathrm{cm}^{\mathrm{2}} \\ $$ Commented by mr W…
Question Number 222961 by Jubr last updated on 12/Jul/25 Answered by mr W last updated on 12/Jul/25 Commented by mr W last updated on 12/Jul/25…
Question Number 222995 by Jubr last updated on 12/Jul/25 Answered by mr W last updated on 12/Jul/25 $${T}={tension}\:{string}\:{around}\:{the}\:{pulley} \\ $$$${A}={acceleration}\:{of}\:{block}\:{M} \\ $$$${a}={acceleration}\:{of}\:{block}\:{m} \\ $$$${assume}\:{there}\:{is}\:{no}\:{friction}. \\…
Question Number 222924 by chidera last updated on 11/Jul/25 Answered by gabthemathguy25 last updated on 11/Jul/25 $$\mathrm{8}×\mathrm{70}=\mathrm{560}\:{kg} \\ $$$$\mathrm{1}\:\mathrm{tonne}\:=\:\mathrm{1000}\:\mathrm{kg} \\ $$$$\Rightarrow\frac{\mathrm{560}}{\mathrm{1000}}=\mathrm{0}.\mathrm{56}\:\mathrm{tonnes} \\ $$ Answered by…
Question Number 222937 by Nicholas666 last updated on 11/Jul/25 $$ \\ $$$$\:\:\:\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{following}\:\mathrm{identity}\:\mathrm{holds}\::\:\:\:\: \\ $$$$\:\:\:\underset{\lambda\in\mathbb{Z}\left[{i}\right]} {\sum}\:\left(\frac{\mathrm{1}}{\left(\mathrm{1}\:+\:\mathrm{3}\lambda\right)^{\mathrm{3}} }\right)\:=\:\frac{\pi^{\mathrm{9}/\mathrm{2}} \:\sqrt{\mathrm{1}\:+\:\sqrt{\mathrm{3}\:}}}{\mathrm{2}^{\mathrm{5}/\mathrm{4}} \:\:\mathrm{3}^{\mathrm{27}/\mathrm{8}} \:\Gamma\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{6}} \:}\:\:\:\:\: \\ $$$$\:\:\:\:\mathrm{Where}\:\mathbb{Z}\left[{i}\right]\:=\:\left\{{a}\:+\:{bi}\::\:{a},{b}\:\in\:\mathbb{Z}\right\}\:\mathrm{denotes}\:\mathrm{gaussian}\:\mathrm{integers}\:!\:\:\:\:\:\:\:\:\: \\ $$$$\: \\…
Question Number 222865 by ejustinianov last updated on 09/Jul/25 $$\pi \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 222781 by MathematicalUser2357 last updated on 07/Jul/25 $$\:\cancel{\underline{\underbrace{\succapprox}}} \\ $$ Answered by AntonCWX8 last updated on 07/Jul/25 $$ \\ $$ Commented by MathematicalUser2357…
Question Number 222783 by MathematicalUser2357 last updated on 07/Jul/25 $$\:\underbrace{ } \\ $$ Answered by AntonCWX8 last updated on 07/Jul/25 $${f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{5}}{x}^{\mathrm{5}} −\frac{\mathrm{5}}{\mathrm{3}}{x}^{\mathrm{3}} +\mathrm{4}{x}+\mathrm{2} \\ $$$${f}'\left({x}\right)={x}^{\mathrm{4}}…