Question Number 134074 by EDWIN88 last updated on 27/Feb/21
![](https://www.tinkutara.com/question/19130.png)
Commented by EDWIN88 last updated on 27/Feb/21
![r = 10 cm](https://www.tinkutara.com/question/Q134075.png)
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{r}\:=\:\mathrm{10}\:\mathrm{cm} \\ $$
Answered by bramlexs22 last updated on 27/Feb/21
![blue area = 2(((π.5^2 )/4)−(5^2 /2)) = ((25π)/2)− 25 ≈ 14.2699](https://www.tinkutara.com/question/Q134076.png)
$$\mathrm{blue}\:\mathrm{area}\:=\:\mathrm{2}\left(\frac{\pi.\mathrm{5}^{\mathrm{2}} }{\mathrm{4}}−\frac{\mathrm{5}^{\mathrm{2}} }{\mathrm{2}}\right) \\ $$$$\:=\:\frac{\mathrm{25}\pi}{\mathrm{2}}−\:\mathrm{25}\:\approx\:\mathrm{14}.\mathrm{2699} \\ $$