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Question-134484




Question Number 134484 by mohammad17 last updated on 04/Mar/21
Commented by Dwaipayan Shikari last updated on 04/Mar/21
General term=(n/(n^2 −(n−1)^2 ))=(n/(2n−1))  lim_(n→∞) (n/(2n−1))=(1/2)   (Sequence converges to (1/2))  And the series is Divergent Σ_(n=1) ^∞ (n/(2n−1))→∞
$${General}\:{term}=\frac{{n}}{{n}^{\mathrm{2}} −\left({n}−\mathrm{1}\right)^{\mathrm{2}} }=\frac{{n}}{\mathrm{2}{n}−\mathrm{1}} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{n}}{\mathrm{2}{n}−\mathrm{1}}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\left({Sequence}\:{converges}\:{to}\:\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$${And}\:{the}\:{series}\:{is}\:{Divergent}\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{n}}{\mathrm{2}{n}−\mathrm{1}}\rightarrow\infty \\ $$

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