Question Number 11327 by 786786AM last updated on 20/Mar/17 $$\mathrm{pl}\:\mathrm{show}\:\mathrm{me}\:\mathrm{typing}\:\mathrm{and}\:\mathrm{shape}\:\mathrm{drawing}\:\mathrm{app}\:\mathrm{for}\:\mathrm{mobile}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 76860 by vishalbhardwaj last updated on 31/Dec/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{having} \\ $$$$\left(\mathrm{2},−\mathrm{2}\right)\:\mathrm{as}\:\mathrm{its}\:\mathrm{centre}\:\mathrm{and}\:\mathrm{passing} \\ $$$$\mathrm{through}\:\mathrm{3x}+\mathrm{y}=\mathrm{14},\:\mathrm{2x}+\mathrm{5y}=\mathrm{18}\:?? \\ $$ Answered by john santu last updated on 31/Dec/19 $${r}\:=\:\sqrt{\:\left(\mathrm{4}−\mathrm{2}\right)^{\mathrm{2}}…
Question Number 142393 by qaz last updated on 31/May/21 $$\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}−\mathrm{1}} {\sum}}\mathrm{sec}^{\mathrm{2}} \left(\frac{\mathrm{k}\pi}{\mathrm{n}}\right)=\mathrm{n}^{\mathrm{2}} ……??? \\ $$ Answered by mindispower last updated on 31/May/21 $$=\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}}…
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Question Number 11321 by Joel576 last updated on 20/Mar/17 $$\mathrm{How}\:\mathrm{many}\:\mathrm{solution}\:\left\{{x},\:{y},\:{z}\right\}\:\mathrm{that}\:\mathrm{fulfilled} \\ $$$${x}\:+\:{y}\:+\:{z}\:=\:\mathrm{99}\:? \\ $$$${x},{y},{z}\:\in\:\mathbb{N} \\ $$ Commented by prakash jain last updated on 22/Mar/17 $$\mathrm{Please}\:\mathrm{have}\:\mathrm{a}\:\mathrm{look}\:\mathrm{at}\:\mathrm{stars}\:\mathrm{and}\:\mathrm{bars}…
Question Number 142389 by alcohol last updated on 31/May/21 $$\int\frac{{e}^{{x}} }{{cosx}}{dx} \\ $$ Answered by ArielVyny last updated on 31/May/21 $$=\left[{e}^{{x}} ×\frac{\mathrm{1}}{{cosx}}\right]−\int{e}^{{x}} ×−\frac{{sinx}}{{cos}^{\mathrm{2}} {x}}{dx} \\…
Question Number 142388 by mathocean1 last updated on 30/May/21 $$\mathrm{n}\:\in\:\mathbb{N},\:\mathrm{b},\:\mathrm{a}\:\in\:\mathbb{N}\:;\:\mathrm{a}\neq\mathrm{0}. \\ $$$$\mathrm{In}\:\mathrm{base}\:\mathrm{10};\:\mathrm{n}=\overline {\mathrm{aabb}}\: \\ $$$$\mathrm{1}.\:\mathrm{show}\:\mathrm{that}\:\mathrm{n}\:\mathrm{is}\:\mathrm{not}\:\mathrm{prime}. \\ $$$$\mathrm{2}.\:\mathrm{Give}\:\mathrm{conditions}\:\mathrm{on}\:\mathrm{b}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{n}\:\mathrm{is}\:\mathrm{perfect}\:\mathrm{square}. \\ $$$$\mathrm{3}.\:\mathrm{Determinate}\:\mathrm{n}\:\mathrm{such}\:\mathrm{that}\:\mathrm{n}\:\mathrm{is}\:\mathrm{a}\: \\ $$$$\mathrm{perfect}\:\mathrm{square}. \\ $$…
Question Number 76855 by aliesam last updated on 31/Dec/19 Commented by aliesam last updated on 31/Dec/19 $${AB}={BC}=……={Fg}={GA} \\ $$$${prove}\:{that}\: \\ $$$${the}\:{area}=\frac{{a}^{\mathrm{2}} }{\mathrm{2}}\left(\pi−\mathrm{7}{tan}\left(\frac{\pi}{\mathrm{14}}\right)\right) \\ $$ Commented…
Question Number 11315 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 20/Mar/17 Commented by chux last updated on 20/Mar/17 $$\mathrm{please}\:\mathrm{can}\:\mathrm{you}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{the}\:\mathrm{name}\:\mathrm{of} \\ $$$$\mathrm{any}\:\mathrm{app}\:\mathrm{for}\:\mathrm{plotting}\:\mathrm{and}\:\mathrm{editing} \\ $$$$\mathrm{graph}. \\ $$ Commented by…