Question Number 226935 by Estevao last updated on 19/Dec/25 Commented by Kassista last updated on 21/Dec/25 Commented by Kassista last updated on 21/Dec/25 Answered by…
Question Number 226936 by Estevao last updated on 19/Dec/25 Answered by Ghisom_ last updated on 19/Dec/25 $$\int\mathrm{2}^{\mathrm{ln}\:{x}} {dx}=\int{x}^{\mathrm{ln}\:\mathrm{2}} {dx}=\frac{{x}^{\mathrm{1}+\mathrm{ln}\:\mathrm{2}} }{\mathrm{1}+\mathrm{ln}\:\mathrm{2}}+{C} \\ $$ Commented by Estevao…
Question Number 226914 by Estevao last updated on 18/Dec/25 Answered by breniam last updated on 19/Dec/25 $$\mathrm{We}\:\mathrm{can}\:\mathrm{concider}\:\mathrm{it}\:\mathrm{only}\:\mathrm{for}\:\mathrm{odd}\:{n},\:\mathrm{because} \\ $$$$\mathrm{real}\:\mathrm{even}\:\mathrm{root}\:\mathrm{of}\:\mathrm{negative}\:\mathrm{number}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{exist}. \\ $$$$=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\left(\mathrm{2}{n}−\mathrm{2}\right)!\left(\mathrm{2}−\mathrm{2}{n}\right)}= \\ $$$$=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\left(\mathrm{2}{n}−\mathrm{1}\right)!}×\sqrt[{\mathrm{2}{n}−\mathrm{1}}]{\frac{\mathrm{2}−\mathrm{2}{n}}{\mathrm{2}{n}−\mathrm{1}}}…
Question Number 226861 by Estevao last updated on 17/Dec/25 Answered by Estevao last updated on 17/Dec/25 $${Go}\:{go}\:{gooooooo} \\ $$ Answered by Tawa11 last updated on…
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Question Number 226866 by Estevao last updated on 17/Dec/25 Commented by Jyrgen last updated on 17/Dec/25 $$\int\sqrt{\mathrm{1}+{x}^{{n}} }{dx}={x}\:_{\mathrm{1}} {F}_{\mathrm{2}} \:\left(−\frac{\mathrm{1}}{\mathrm{2}},\:\frac{\mathrm{1}}{{n}};\:\mathrm{1}+\frac{\mathrm{1}}{{n}};\:−{x}^{{n}} \right) \\ $$ Commented by…
Question Number 226830 by Estevao last updated on 16/Dec/25 Answered by TonyCWX last updated on 17/Dec/25 $$\mathrm{27}\:=\:\mathrm{3}^{\mathrm{3}} \:=\:^{\mathrm{2}} \mathrm{3} \\ $$$$\:^{\mathrm{2}} {x}\:=\:\mathrm{2} \\ $$$${x}^{{x}} =\mathrm{2}…
Question Number 226736 by ajfour last updated on 12/Dec/25 Commented by ajfour last updated on 12/Dec/25 $${Lets}\:{attempt}\:{the}\:\mathrm{25}\:{million}\:{dollar}\: \\ $$$${question}\:{that}\:{i}\:{solved}\:{then}\: \\ $$$${satisfactorily}\:{with} \\ $$$${sir}\:{MJS},\:{still}\:{in}\:{another}\:{better} \\ $$$${way}!…
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