Question Number 210180 by BHOOPENDRA last updated on 02/Aug/24 Commented by mr W last updated on 02/Aug/24 $${is}\:{the}\:{load}\:{acting}\:{in}\:{the}\:{shear}\:{center} \\ $$$${in}\:{both}\:{cases}? \\ $$ Commented by BHOOPENDRA…
Question Number 210017 by klipto last updated on 28/Jul/24 $$ \\ $$$$\boldsymbol{\mathrm{MATH}}−\boldsymbol{\mathrm{WHIZZKID}} \\ $$$$\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{kamke}}\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{genral}} \\ $$$$\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{differential}}\:\boldsymbol{\mathrm{equation}} \\ $$$$\mathrm{1}.\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}''+\boldsymbol{\mathrm{x}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}'−\mathrm{2}\boldsymbol{\mathrm{y}}=\mathrm{0} \\ $$$$−−−−−−−−− \\ $$$$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{forbenius}}\:\boldsymbol{\mathrm{mtd}} \\…
Question Number 209944 by Tawa11 last updated on 26/Jul/24 Commented by mr W last updated on 26/Jul/24 $${f}=\frac{\mathrm{100}×\mathrm{6}}{\mathrm{2}\pi×\mathrm{2}.\mathrm{5}}=\mathrm{38}.\mathrm{2}\:{Hz} \\ $$ Terms of Service Privacy Policy…
Question Number 209886 by Tawa11 last updated on 24/Jul/24 Commented by Tawa11 last updated on 25/Jul/24 $$\mathrm{g}\:=\:\mathrm{9}.\mathrm{8}\:\mathrm{ms}^{−\mathrm{2}} \\ $$ Answered by mr W last updated…
Question Number 209847 by SonGoku last updated on 23/Jul/24 Answered by mr W last updated on 23/Jul/24 $${depth}\:={h} \\ $$$${h}=\sqrt{\mathrm{23}^{\mathrm{2}} −\left(\frac{\mathrm{53}−\mathrm{41}}{\mathrm{2}}\right)^{\mathrm{2}} }=\sqrt{\mathrm{493}}=\mathrm{22}.\mathrm{20}{m} \\ $$$${cross}\:{section}\:{area}\:={A} \\…
Question Number 209856 by SonGoku last updated on 23/Jul/24 Commented by SonGoku last updated on 23/Jul/24 $$\mathrm{How}\:\mathrm{do}\:\mathrm{I}\:\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{this}\:\mathrm{figure}? \\ $$ Commented by mr W last updated…
Question Number 209631 by York12 last updated on 17/Jul/24 $$\mathrm{Let}\:{u}_{{n}} \:\mathrm{be}\:\mathrm{a}\:\mathrm{set}\:\mathrm{satisfying}\:{u}_{\mathrm{1}} =\mathrm{1}\:\&\:{u}_{{n}+\mathrm{1}} ={u}_{{n}} +\frac{\mathrm{ln}\:{n}}{{u}_{{n}} }\:\:,\:\forall\:{n}\:\geqslant\mathrm{1} \\ $$$$\mathrm{1}.\:\mathrm{Prove}\:\mathrm{that}\:{u}_{\mathrm{2023}} >\sqrt{\mathrm{2023}.\mathrm{ln}\:\mathrm{2023}}. \\ $$$$\mathrm{2}.\:\mathrm{Find}:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{u}_{{n}} .\mathrm{ln}\:{n}}{{n}}. \\ $$ Terms…
Question Number 209432 by Tawa11 last updated on 10/Jul/24 A body is projected vertically upwards with a speed of 20m/s. Find the time in seconds…
Question Number 209430 by Tawa11 last updated on 09/Jul/24 Answered by mr W last updated on 10/Jul/24 $$\left.\mathrm{1}\right) \\ $$$$\omega_{\mathrm{0}} =\sqrt{\frac{{k}}{{m}}} \\ $$$$\zeta=\frac{{c}}{\mathrm{2}\sqrt{{mk}}} \\ $$$$\omega_{{r}}…
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